// Run time: 0.010
#include <stdio.h>
int main()
{
int num; // 輸入組數
int n;
int i; // for loop count
int weight;
double s, e; // a(0) and a(n+1)
double sum, total;
scanf("%d", &num);
while (num--)
{
sum = total = weight = 0;
scanf("%d", &n);
scanf("%lf%lf", &s, &e);
double arr[n];
for ( i = 0; i < n; i++)
scanf("%lf", &arr[i]);
sum = s*n+e;
for ( i = n-1; i >= 0; i--)
total += (weight+=2)*arr[i];
printf("%.2lf\n", (sum-total)/(n+1));
if (num)
printf("\n");
}
return 0;
}
2009年2月21日 星期六
Q10014: Simple calculations
2009年2月20日 星期五
Q10010: Where's Waldorf?
// Run time: 0.000
#include <stdio.h>
#include <ctype.h>
#include <string.h>
#define N 50
char str[N][N+1];
char arr[N+1];
void check(int length, char ch, int row, int len);
bool test(int row, int col, int length, int row, int len);
int main()
{
int n;
int row, len;
int length; // check string's length
int num;
int i, j;
scanf("%d", &n);
while (n--)
{
scanf("%d%d\n", &row, &len);
// input
for ( i = 0; i < row; i++)
gets(str[i]);
// toupper
for ( i = 0; i < row; i++)
for ( j = 0; j < len; j++)
str[i][j] = toupper(str[i][j]);
scanf("%d\n", &num);
// input for check string
while (num--)
{
gets(arr);
length = strlen(arr);
// toupper case
for ( i = 0; i < length; i++)
arr[i] = toupper(arr[i]);
check(length, arr[0], row, len);
}
if (n)
printf("\n");
}
return 0;
}
void check(int length, char ch, int row, int len)
{
int i, j;
for ( i = 0; i < row; i++)
for ( j = 0; j < len; j++)
if (str[i][j] == ch)
if (test(i, j, length, row, len))
return;
}
bool test(int r, int c, int length, int row, int len)
{
int i, j, k;
// 往左看
if (c-length >= -1)
{
for ( i = c-1, j = 1; j < length; i--, j++)
if (str[r][i] != arr[j])
break;
if (j == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往右看
if (len-c >= length)
{
for ( i = c+1, j = 1; j < length; i++, j++)
if (str[r][i] != arr[j])
break;
if (j == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往上看
if (r-length >= -1)
{
for ( i = r-1, j = 1; j < length; i--, j++)
if (str[i][c] != arr[j])
break;
if (j == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往下看
if (r+length <= row)
{
for ( i = r+1, j = 1; j < length; i++, j++)
if (str[i][c] != arr[j])
break;
if (j == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往左上
if (c-length >= -1 && r-length >= -1)
{
for ( i = r-1, j = c-1, k = 1; k < length; i--, j--, k++)
if (str[i][j] != arr[k])
break;
if (k == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往右下
if (len-c >= length && r+length <= row)
{
for ( i = r+1, j = c+1, k = 1; k < length; i++, j++, k++)
if (str[i][j] != arr[k])
break;
if (k == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往左下
if (c-length >= -1 && r+length <= row)
{
for ( i = r+1, j = c-1, k = 1; k < length; i++, j--, k++)
if (str[i][j] != arr[k])
break;
if (k == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
// 往右上
if (len-c >= length && r-length >= -1)
{
for ( i = r-1, j = c+1, k = 1; k < length; i--, j++, k++)
if (str[i][j] != arr[k])
break;
if (k == length)
{
printf("%d %d\n", r+1, c+1);
return true;
}
}
return false;
}
2009年2月18日 星期三
Q10008: What's Cryptanalysis
// Run time: 0.000
#include <stdio.h>
#include <ctype.h>
#define N 26
int arr[N];
bool state[N];
void calculate(char ch);
void sort();
int select();
int main()
{
char ch;
int n;
int i;
bool s = true;
scanf("%d\n", &n);
while (n--)
{
while (true)
{
if ((ch = getchar()) == '\n')
break;
calculate(ch);
}
}
sort();
return 0;
}
void calculate(char ch)
{
ch = toupper(ch);
if (isalpha(ch))
arr[ch-'A']++;
}
void sort()
{
int max, index;
int i;
for (; ;)
{
index = select();
if (index == -1)
return;
max = arr[index];
state[index] = true;
for ( i = 0; i < N; i++)
{
if (!state[i] && arr[i] > max)
{
state[index] = false;
state[i] = true;
max = arr[i];
index = i;
}
}
printf("%c %d\n", index+'A', arr[index]);
}
}
int select()
{
int i;
for ( i = 0; i < N; i++)
if (!state[i] && arr[i])
return i;
return -1;
}
2009年2月17日 星期二
Q825: Walking on the Safe Side
// Run time: 0.000
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define N 101
int arr[N][N];
char str[1000];
void reset(int row, int col);
void assign(int row, int len);
void check(int row, int col);
int calculate(int row, int col);
int main()
{
int n, row, col;
int count, len;
int i;
scanf("%d", &n);
while (n--)
{
scanf("%d%d\n", &row, &col);
reset(row, col);
for ( i = 1; i <= row; i++)
{
gets(str);
len = strlen(str);
assign(i, len);
}
check(row, col);
count = calculate(row, col);
printf("%d\n", count);
if (n) printf("\n");
}
}
void reset(int row, int col)
{
int i, j;
for ( i = 1; i <= row; i++)
for ( j = 1; j <= col; j++)
arr[i][j] = 1;
}
void assign(int row, int len)
{
int i, tmp;
bool state = false;
for ( i = 0; i < len; i++)
{
if (str[i] == ' ') continue;
tmp = atoi(str+i);
if (state)
arr[row][tmp] = 0;
else
state = true;
}
}
void check(int row, int col)
{
// 因為只能往右或下不能往左或上
// 所以要做確認是否有誤
int i, index;
for ( i = 2; i < row; i++)
if (!arr[i][1])
break;
index = i;
if ( i != row)
for ( i = index; i <= row; i++)
arr[i][1] = 0;
for ( i = 2; i < col; i++)
if (!arr[1][i])
break;
index = i;
if ( i != col)
for ( i = index; i <= col; i++)
arr[1][i] = 0;
}
int calculate(int row, int col)
{
int i, j;
for ( i = 2; i <= row; i++)
for ( j = 2; j <= col; j++)
arr[i][j] = arr[i][j] ? arr[i][j-1] + arr[i-1][j] : 0;
return arr[row][col];
}
Q846: Steps
// Run time: 0.010
#include <stdio.h>
#include <math.h>
int calculate(int x, int y);
int main()
{
int n;
int step;
int a, b;
scanf("%d", &n);
while (n--)
{
scanf("%d%d", &a, &b);
step = calculate(a, b);
printf("%d\n", step);
}
return 0;
}
int calculate(int x, int y)
{
int sum = 0;
int weight = 2;
int n, cnt;
n = y-x;
if (!n)
return 0;
for ( ;sum < n; sum += weight, weight += 2);
x = (int)sqrt(sum);
if (n > x*x)
cnt = 2*x;
else
cnt = 2*x-1;
return cnt;
}
2009年2月16日 星期一
Q729: The Hamming Distance Problem
// Run time: 0.820
#include <stdio.h>
#define N 16
int arr[N];
int len, distance;
void test(int len);
void calculate();
void print();
int main()
{
int n;
scanf("%d", &n);
while (n--)
{
scanf("%d%d", &len, &distance);
test(len);
if (n)
printf("\n");
}
return 0;
}
void test(int len)
{
int i, j;
int prod = 1;
for ( i = 0; i < len; i++)
{
arr[i] = 0;
prod *= 2;
}
for ( i = 0; i < prod; i++)
{
calculate();
arr[0]++;
for ( j = 0; j < len-1; j++)
{
if (arr[j] >= 2)
{
arr[j+1] += arr[j]/2;
arr[j] %= 2;
}
}
}
}
void calculate()
{
int i;
int count = 0;
for ( i = 0; i < len; i++)
count = arr[i] ? count+1 : count;
if (count == distance)
print();
}
void print()
{
int i;
for ( i = len-1; i >= 0; i--)
printf("%d", arr[i]);
printf("\n");
}
2009年2月15日 星期日
Q694: The Collatz Sequence
/*
The same as Q100
Run time: 0.050
*/
#include <stdio.h>
int calculate(long long int n, long long int limit);
int main()
{
long long int num, limit;
int count;
int cnt = 0;
while (scanf("%lld%lld", &num, &limit))
{
if (num < 0 && limit < 0)
break;
count = calculate(num, limit);
printf("Case %d: A = %lld, limit = %lld, number of terms = %d\n", ++cnt, num, limit, count);
}
}
int calculate(long long int n, long long int limit)
{
int len = 1;
while (n != 1)
{
n = n%2 ? 3*n+1 : n/2;
if (n > limit)
return len;
len++;
}
return len;
}
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